Form a polynomial whose real zeros and degree are given.
Zeros: $-2,0,5$; degree: 3
Type a polynomial with integer coefficients and a leading coefficient of 1.
$f(x)=◻$ (Simplify your answer. $)$

Step 1 ：The zeros of a polynomial are the values of x for which the polynomial equals zero. If we know the zeros of a polynomial, we can form the polynomial by multiplying factors of the form $(x-zero)$. In this case, the zeros are -2, 0, and 5. So, the polynomial can be formed by multiplying the factors $(x-(-2))$, $(x-0)$, and $(x-5)$.

Step 2 ：The degree of the polynomial is the highest power of x in the polynomial. Since the degree is 3, and we have 3 factors, each of degree 1, we don't need to add any more factors.

Step 3 ：Thus, the polynomial is $x\ast (x-5)\ast (x+2)$.

Step 4 ：Simplifying this expression, we get the same polynomial $x\ast (x-5)\ast (x+2)$.

Step 5 ：Final Answer: The polynomial with integer coefficients and a leading coefficient of 1, whose real zeros are -2, 0, and 5, and degree is 3, is $\boxed{{\displaystyle x(x-5)(x+2)}}$.