Cities and companies find that the cost of pollution control increases along with the percentage of pollutants to be removed in a situation. Suppose that the cost C, in dollars, of removing p\% of the pollutants from a chemical spill is given below. Complete parts (a) through (d).
$C (p) = \frac{40, 000}{100 - p}$
(a) Find $C (0), C (20), C (80)$ , and $C (90)$ .
$C (0) = $ ◻$ (Round to the nearest whole number as necessary. Simplify your answer.)

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Answer

Final Answer: $C (0) = $ 400$ , $C (20) = $ 500$ , $C (80) = $ 2000$ , and $C (90) = $ 4000$ .

Steps

Step 1 ：Given the cost function $C (p) = \frac{40, 000}{100 - p}$ , we are asked to find the cost of removing certain percentages of pollutants.

Step 2 ：Substitute $p = 0$ into the function to find $C (0)$ , which gives $C (0) = \frac{40, 000}{100 - 0} = $ 400$ .

Step 3 ：Substitute $p = 20$ into the function to find $C (20)$ , which gives $C (20) = \frac{40, 000}{100 - 20} = $ 500$ .

Step 4 ：Substitute $p = 80$ into the function to find $C (80)$ , which gives $C (80) = \frac{40, 000}{100 - 80} = $ 2000$ .

Step 5 ：Substitute $p = 90$ into the function to find $C (90)$ , which gives $C (90) = \frac{40, 000}{100 - 90} = $ 4000$ .

Step 6 ：Final Answer: $C (0) = $ 400$ , $C (20) = $ 500$ , $C (80) = $ 2000$ , and $C (90) = $ 4000$ .