Find $\int \frac{x-1}{x^{2}} d x$
Final Answer: \(\boxed{\log(x) + \frac{1}{x} + C}\)
Step 1 :Given the integral problem \(\int \frac{x-1}{x^{2}} dx\)
Step 2 :We can rewrite the integrand as \(\frac{x}{x^{2}} - \frac{1}{x^{2}}\)
Step 3 :Now, we can integrate each term separately
Step 4 :The integral of the function \(\frac{x-1}{x^{2}}\) is \(\log(x) + \frac{1}{x} + C\), where \(C\) is the constant of integration
Step 5 :Final Answer: \(\boxed{\log(x) + \frac{1}{x} + C}\)