Maricopa's Success scholarship fund receives a gift of $\mathrm{\$}$ 95000. The money is invested in stocks, bonds, and CDs. CDs pay $3\mathrm{\%}$ interest, bonds pay $4\mathrm{\%}$ interest, and stocks pay $9.6\mathrm{\%}$ interest. Maricopa Success invests $\mathrm{\$}15000$ more in bonds than in CDs. If the annual income from the investments is $\mathrm{\$}4620$, how much was invested in each account?

Step 1 ：Let's denote the amount invested in CDs as x, the amount invested in bonds as x + 15000, and the amount invested in stocks as 95000 - x - (x + 15000).

Step 2 ：We know that the total interest earned is $4620. We can set up an equation to represent this: $0.03x$ (interest from CDs) + $0.04(x+15000)$ (interest from bonds) + $0.096(95000-x-(x+15000))$ (interest from stocks) = 4620.

Step 3 ：Solving this equation gives us the value of x, which represents the amount invested in CDs.

Step 4 ：Substituting x into the expressions for the amounts invested in bonds and stocks gives us the respective amounts.

Step 5 ：Final Answer: The amount invested in CDs is $\boxed{{\displaystyle \mathrm{\$}30000}}$, in bonds is $\boxed{{\displaystyle \mathrm{\$}45000}}$, and in stocks is $\boxed{{\displaystyle \mathrm{\$}20000}}$.