c) 3 i^{2}-14 i+16=0

Question

Accepted Answer

Step:1 ：Given the quadratic equation in complex numbers: (3 i^{2}-14 i+16=0)Step:2 ：Identify the coefficients as: (a=3), (b=-14), and (c=16)Step:3 ：Substitute these values into the quadratic formula: (x=frac{-bpmsqrt{b^{2}-4ac}}{2a})Step:4 ：Calculate the discriminant: (D = (2+0j))Step:5 ：Find the first solution: (sol1 = (2+0j))Step:6 ：Find the second solution: (sol2 = (2.6666666666666665+0j))Step:7 ：Final Answer: The solutions to the equation (3 i^{2}-14 i+16=0) are (boxed{2}) and (boxed{frac{8}{3}})

Answer

Step: 1 ：Given the quadratic equation in complex numbers: (3 i^{2}-14 i+16=0)Step: 2 ：Identify the coefficients as: (a=3), (b=-14), and (c=16)Step: 3 ：Substitute these values into the quadratic formula: (x=frac{-bpmsqrt{b^{2}-4ac}}{2a})Step: 4 ：Calculate the discriminant: (D = (2+0j))Step: 5 ：Find the first solution: (sol1 = (2+0j))Step: 6 ：Find the second solution: (sol2 = (2.6666666666666665+0j))Step: 7 ：Final Answer: The solutions to the equation (3 i^{2}-14 i+16=0) are (boxed{2}) and (boxed{frac{8}{3}})

c) $3 i^{2} - 14 i + 16 = 0$

Answer

Popular Problems

c) 3i2−14i+16=0

Answer

Popular Problems

c) $3 i^{2} - 14 i + 16 = 0$