Find the center and the radius of the circle. Then graph the circle.
$x^{2} + y^{2} = 49$
The center is
(Simplify your answer. Type an ordered pair.)

Answer

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Answer

Therefore, the center of the circle is $(0, 0)$ and the radius is $7$ .

Steps

Step 1 ：The given equation is already in the standard form of a circle equation, which is $x^{2} + y^{2} = r^{2}$ .

Step 2 ：The center of the circle is at the origin (0,0) because there are no $x$ or $y$ terms.

Step 3 ：The radius of the circle is the square root of the constant term on the right side of the equation. So, $r = \sqrt{49} = 7$ .

Step 4 ：Therefore, the center of the circle is $(0, 0)$ and the radius is $7$ .