Problem

Question 4
Given: g(n)=n3+5n and h(n)=3n+3
Find: h(g(n+1))
4n3+12n23n+14
3n3+9n2+24n+21
6n24n+6
There is no correct answer given.
9n324n+18

Answer

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Answer

So, the final answer is 3n3+9n2+24n+21.

Steps

Step 1 :Given the functions g(n)=n3+5n and h(n)=3n+3, we are asked to find the value of h(g(n+1)).

Step 2 :First, we need to find the value of g(n+1).

Step 3 :Substituting n+1 into g(n), we get g(n+1)=(n+1)3+5(n+1).

Step 4 :Next, we substitute this value into h(n) to get h(g(n+1))=3g(n+1)+3.

Step 5 :Substituting g(n+1) into this equation, we get h(g(n+1))=3((n+1)3+5(n+1))+3.

Step 6 :Expanding this equation, we get h(g(n+1))=3n3+9n2+24n+21.

Step 7 :So, the final answer is 3n3+9n2+24n+21.

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