Now consider a larger group of students: Alice, Bob, Claire, David, Emma, Frank, George, Helen, Ian, Jessica, Kevin, and Lisa. They are to be divided into two groups, Group A and Group B, for a class activity. Each group must have exactly 6 students.
iv. If Lisa wants to be in the same group as either Claire or Frank, how many different divisions are possible?

Step 1 ：Break the problem into two cases: (1) Lisa and Claire are in the same group, but Frank is not. (2) Lisa and Frank are in the same group, but Claire is not.

Step 2 ：For case 1, there are 9 students left to choose from, and we need to choose 4 more students to complete the group of 6. The number of ways to do this is \(\binom{9}{4} = 126\).

Step 3 ：For case 2, there are also 9 students left to choose from, and we need to choose 4 more students to complete the group of 6. The number of ways to do this is also \(\binom{9}{4} = 126\).

Step 4 ：Add the number of ways for both cases to get the total number of divisions: \(126 + 126 = 252\).

Step 5 ：\(\boxed{252}\) different divisions are possible where Lisa is in the same group as either Claire or Frank.