Now consider a larger group of students: Alice, Bob, Claire, David, Emma, Frank, George, Helen, Ian, Jessica, Kevin, and Lisa. They are to be divided into two groups, Group A and Group B, for a class activity. Each group must have exactly 6 students.
iv. If Lisa wants to be in the same group as either Claire or Frank, how many different divisions are possible?

Step 1 ：Break the problem into two cases: (1) Lisa and Claire are in the same group, but Frank is not. (2) Lisa and Frank are in the same group, but Claire is not.

Step 2 ：For case 1, there are 9 students left to choose from, and we need to choose 4 more students to complete the group of 6. The number of ways to do this is $(\genfrac{}{}{0ex}{}{9}{4})=126$.

Step 3 ：For case 2, there are also 9 students left to choose from, and we need to choose 4 more students to complete the group of 6. The number of ways to do this is also $(\genfrac{}{}{0ex}{}{9}{4})=126$.

Step 4 ：Add the number of ways for both cases to get the total number of divisions: $126+126=252$.

Step 5 ：$\boxed{{\displaystyle 252}}$ different divisions are possible where Lisa is in the same group as either Claire or Frank.