Problem

b) What rill be the population in 8 years? Vear? poplativn in $+=8$
\[
\begin{array}{l}
P=1000\left(\frac{81}{16}\right)^{\frac{-8}{4}} \quad P=34 \\
P=1000\left(\frac{81}{16}\right)^{-2} \quad \vdots \text { the popurapich will } \\
P=1000(0.0391 \text { be } 39 i 18 \text { years }
\end{array}
\]
2. A shark $p^{\prime}$, is created in a rectangular shape. It can be represented approximately by the trinomial
\[
15 x^{2}-2 x-8
\]
a) Factor the expression $15 x^{2}-2 x-8$ to find binomials that represent the length and width of the pen.
14
\[
\begin{aligned}
15 x^{2}-2 x-8-12 \times 10 & =-120 \\
-12+10 & =-2
\end{aligned}
\]
b) If $\mathrm{x}$ represents $18 \mathrm{~m}$, what are the length and width of the pen, in meters?
/1

Answer

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Answer

\(\boxed{3.\text{ The length and width of the pen when }x = 18\text{ meters are 4816 square meters.}}\)

Steps

Step 1 :First, we need to find the population in 8 years using the formula \(P = 1000 * (\frac{81}{16})^{-\frac{8}{4}}\).

Step 2 :Calculating the population, we get \(P \approx 39.018\).

Step 3 :Next, we need to factor the expression \(15x^2 - 2x - 8\).

Step 4 :Factoring the expression, we get \((3x + 2)(5x - 4)\).

Step 5 :Finally, we need to find the length and width of the pen when \(x = 18\) meters.

Step 6 :Substituting \(x = 18\) into the factored expression, we get \((3(18) + 2)(5(18) - 4)\).

Step 7 :Calculating the length and width, we get \(4816\) square meters.

Step 8 :\(\boxed{1.\text{ The population in 8 years will be approximately 39.}}\)

Step 9 :\(\boxed{2.\text{ The factored expression for the pen is }(3x + 2)(5x - 4).}\)

Step 10 :\(\boxed{3.\text{ The length and width of the pen when }x = 18\text{ meters are 4816 square meters.}}\)

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