int frac{1}{x^{2}-1} d x

Question

Accepted Answer

Step:1 ：Perform partial fraction decomposition: (frac{1}{x^2 - 1} = frac{1/2}{x - 1} - frac{1/2}{x + 1})Step:2 ：Integrate each part separately: (int frac{1}{x^{2}-1} d x = boxed{frac{1}{2} ln|x^2 - 1| + C})

Answer

Step: 1 ：Perform partial fraction decomposition: (frac{1}{x^2 - 1} = frac{1/2}{x - 1} - frac{1/2}{x + 1})Step: 2 ：Integrate each part separately: (int frac{1}{x^{2}-1} d x = boxed{frac{1}{2} ln|x^2 - 1| + C})

$\int \frac{1}{x^{2} - 1} d x$

Answer

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$\int \frac{1}{x^{2} - 1} d x$