$x^{2} + y^{2} - 8 x + 16 y - 1 = 0$ is the equation of a circle with center $(h, k)$ and radius $r$ for:
$h =$

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Final Answer: $4.0$

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Step 1 ：The general equation of a circle is given by $(x - h)^{2} + (y - k)^{2} = r^{2}$ . Comparing this with the given equation, we can see that the coefficients of $x$ and $y$ are $- 2 h$ and $2 k$ respectively.

Step 2 ：Therefore, we can find $h$ by dividing the coefficient of $x$ by $- 2$ .

Step 3 ：So, $h = 4.0$

Step 4 ：Final Answer: $4.0$

x2+y2−8x+16y−1=0 is the equation of a circle with center (h,k) and radius r for:h=

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$x^{2} + y^{2} - 8 x + 16 y - 1 = 0$ is the equation of a circle with center $(h, k)$ and radius $r$ for:
$h =$