Evaluate the integral.
\[
\int_{0}^{\pi / 6} 3 \sec ^{2} x d x
\]
Final Answer: \(\boxed{\sqrt{3}}\)
Step 1 :The integral of \(\sec^2(x)\) is \(\tan(x)\). Therefore, the integral of \(3\sec^2(x)\) is \(3\tan(x)\).
Step 2 :We need to evaluate this from 0 to \(\frac{\pi}{6}\).
Step 3 :The integral of \(3\sec^2(x)\) from 0 to \(\frac{\pi}{6}\) is \(\sqrt{3}\).
Step 4 :Final Answer: \(\boxed{\sqrt{3}}\)