Find the probability $P\left(E^{C}\right)$ if $P(E)=0.23$.

The probability $\mathrm{P}\left(\mathrm{E}^{\mathrm{C}}\right)$ is (Simplify your answer.)

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Answer

Final Answer: The probability $P\left(E^{C}\right)$ is $\boxed{0.77}$

Steps

Step 1 ：Given that the probability of event E, denoted as $P(E)$, is 0.23

Step 2 ：The probability of the complement of event E, denoted as $P(E^{C})$, is calculated by subtracting $P(E)$ from 1

Step 3 ：Substitute $P(E)$ into the equation, we get $P(E^{C}) = 1 - P(E) = 1 - 0.23$

Step 4 ：After calculating, we find that $P(E^{C}) = 0.77$

Step 5 ：Final Answer: The probability $P\left(E^{C}\right)$ is $\boxed{0.77}$