The following involves taking a multiple-choice exam and guessing on every single question. The test has 4 questions, and each question has 4 possible responses, of which only 1 is correct. Compute the following probabilities.

The probability of getting at least 2 questions correct. Write your final answer as a percent rounded two two decimal places.
Number
$\%$

Step 1 ：We are given a multiple-choice exam with 4 questions, each question has 4 possible answers and only 1 is correct. We are asked to find the probability of guessing at least 2 questions correctly.

Step 2 ：We can use the binomial probability formula to solve this problem, which is: \(P(X=k) = C(n, k) * (p^k) * ((1-p)^(n-k))\), where \(P(X=k)\) is the probability of getting k successes in n trials, \(C(n, k)\) is the number of combinations of n items taken k at a time, p is the probability of success on a single trial, n is the number of trials, and k is the number of successes.

Step 3 ：In this case, n=4 (the number of questions), p=1/4 (the probability of guessing a question correctly), and we want to find the probability of getting at least 2 questions correct, so we need to calculate \(P(X=2)\), \(P(X=3)\), and \(P(X=4)\) and add them together.

Step 4 ：By calculating, we find that the probability of getting at least 2 questions correct is approximately 0.26171875.

Step 5 ：Converting this to a percentage and rounding to two decimal places, we get 26.17%.

Step 6 ：Final Answer: The probability of getting at least 2 questions correct is \(\boxed{26.17\%}\).