Find the center and radius of the circle. Write the standard form of the equation.
The center of the circle is $(\mathrm{h}, \mathrm{k})=(-3,-1)$
(Type an ordered pair.)
The radius of the circle is $r=3$.
The equation of the circle in standard form is
(Type your answer in standard form.)
Answer
Final Answer: The equation of the circle in standard form is \(\boxed{(x + 3)^2 + (y + 1)^2 = 9}\).
Step 1 ：The center of the circle is given as (-3,-1).
Step 2 ：The radius of the circle is given as 3.
Step 3 ：The standard form of the equation of a circle is given by \((x-h)^2 + (y-k)^2 = r^2\), where \((h, k)\) is the center of the circle and \(r\) is the radius.
Step 4 ：Substitute the given values into the standard form to get the equation of the circle: \((x - (-3))^2 + (y - (-1))^2 = 3^2\).
Step 5 ：Simplify the equation to get the final answer: \((x + 3)^2 + (y + 1)^2 = 9\).
Step 6 ：Final Answer: The equation of the circle in standard form is \(\boxed{(x + 3)^2 + (y + 1)^2 = 9}\).
