What is the vertex of the parabola y=-x^{2}+3 ?

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Accepted Answer

Step:1 ：The vertex of a parabola given by the equation (y = ax^2 + bx + c) is at the point ((-b/2a, f(-b/2a))).Step:2 ：For the given equation (y = -x^2 + 3), (a = -1) and (b = 0).Step:3 ：Substituting these values into the formula, we find that the x-coordinate of the vertex is (0).Step:4 ：Substituting (x = 0) into the equation, we find that the y-coordinate of the vertex is (3).Step:5 ：Therefore, the vertex of the parabola (y = -x^2 + 3) is (boxed{(0, 3)}).

Answer

Step: 1 ：The vertex of a parabola given by the equation (y = ax^2 + bx + c) is at the point ((-b/2a, f(-b/2a))).Step: 2 ：For the given equation (y = -x^2 + 3), (a = -1) and (b = 0).Step: 3 ：Substituting these values into the formula, we find that the x-coordinate of the vertex is (0).Step: 4 ：Substituting (x = 0) into the equation, we find that the y-coordinate of the vertex is (3).Step: 5 ：Therefore, the vertex of the parabola (y = -x^2 + 3) is (boxed{(0, 3)}).

What is the vertex of the parabola $y=-x^{2}+3 ?$

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