$(-2+3 i)(7-4 i)=$
\(\boxed{-2+29 i}\) is the final answer.
Step 1 :Given two complex numbers, \((-2+3 i)\) and \((7-4 i)\), we are to find the product of these two numbers.
Step 2 :The multiplication of complex numbers is done in the same way as the multiplication of binomials. We just need to remember that \(i^2 = -1\).
Step 3 :Multiplying the two complex numbers, we get \((-2+3 i)(7-4 i)\).
Step 4 :Solving this, we get \((-2+29 i)\).
Step 5 :\(\boxed{-2+29 i}\) is the final answer.