Write the quadratic equation whose roots are 2 and -3 , and whose leading coefficient is 2 . (Use the letter $x$ to represent the variable.)
\(\boxed{2x^2 + 2x - 12 = 0}\) is the final answer.
Step 1 :Given the roots of the quadratic equation are 2 and -3, and the leading coefficient is 2.
Step 2 :Using the relationships that the sum of the roots is \(-\frac{b}{a}\) and the product of the roots is \(\frac{c}{a}\), we can find the values of b and c.
Step 3 :Substituting the given values, we get b = -2 and c = -12.
Step 4 :Substituting these values into the standard form of the quadratic equation \(ax^2 + bx + c = 0\), we get the equation \(2x^2 + 2x - 12 = 0\).
Step 5 :\(\boxed{2x^2 + 2x - 12 = 0}\) is the final answer.