Find $s(t)$, where $s(t)$ represents the position function and $v(t)$ represents the velocity function.
\[
v(t)=3 t^{2}, s(0)=6
\]
\[
s(t)=
\]
Therefore, the position function is \(s(t) = t^3 + 6\).
Step 1 :Given the velocity function \(v(t) = 3t^2\), we can find the position function \(s(t)\) by integrating \(v(t)\).
Step 2 :Integrating \(v(t) = 3t^2\) with respect to \(t\) gives \(s(t) = t^3 + C\), where \(C\) is the constant of integration.
Step 3 :We can find \(C\) by using the initial condition \(s(0) = 6\). Substituting these values into the equation gives \(6 = 0 + C\), so \(C = 6\).
Step 4 :Therefore, the position function is \(s(t) = t^3 + 6\).