Given the functions below, find $(g + h) (1)$ .
$\begin{array}{l} g (x) = x^{2} + 4 + 2 x \\ h (x) = - 3 x + 2 \end{array}$
12
$- 6$
6
8

Answer

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Answer

So, the value of $(g + h) (1)$ is $6$ .

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Step 1 ：Given the functions $g (x) = x^{2} + 4 + 2 x$ and $h (x) = - 3 x + 2$ , we are asked to find the value of $(g + h) (1)$ . This means we need to find the sum of the functions $g (x)$ and $h (x)$ at $x = 1$ .

Step 2 ：First, we find the value of $g (1)$ by substituting $x = 1$ into the function $g (x)$ . This gives us $g (1) = 1^{2} + 4 + 2 (1) = 7$ .

Step 3 ：Next, we find the value of $h (1)$ by substituting $x = 1$ into the function $h (x)$ . This gives us $h (1) = - 3 (1) + 2 = - 1$ .

Step 4 ：Finally, we add these two values together to get the final answer. This gives us $(g + h) (1) = g (1) + h (1) = 7 + (- 1) = 6$ .

Step 5 ：So, the value of $(g + h) (1)$ is $6$ .

Given the functions below, find (g+h)(1).g(x)=x2+4+2xh(x)=−3x+212−668

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Given the functions below, find $(g + h) (1)$ .
$\begin{array}{l} g (x) = x^{2} + 4 + 2 x \\ h (x) = - 3 x + 2 \end{array}$
12
$- 6$
6
8