Find the first and second derivatives.
\[
y=\frac{2 x^{5}+6}{x^{3}}
\]
Final Answer: The first derivative is \(\boxed{10x - \frac{3(2x^5 + 6)}{x^4}}\) and the second derivative is \(\boxed{-20 + \frac{12(2x^5 + 6)}{x^5}}\).
Step 1 :We are given the function \(y = \frac{2x^5 + 6}{x^3}\).
Step 2 :We need to find the first and second derivatives of this function.
Step 3 :First, we find the first derivative using the quotient rule. The quotient rule states that the derivative of a quotient of two functions is the denominator times the derivative of the numerator minus the numerator times the derivative of the denominator, all over the square of the denominator.
Step 4 :Applying the quotient rule, we get the first derivative as \(y' = 10x - \frac{3(2x^5 + 6)}{x^4}\).
Step 5 :Next, we find the second derivative by taking the derivative of the first derivative.
Step 6 :Applying the derivative rules, we get the second derivative as \(y'' = -20 + \frac{12(2x^5 + 6)}{x^5}\).
Step 7 :Final Answer: The first derivative is \(\boxed{10x - \frac{3(2x^5 + 6)}{x^4}}\) and the second derivative is \(\boxed{-20 + \frac{12(2x^5 + 6)}{x^5}}\).