Write the standard form of the equation of the circle described below.
Center $(-8,3), r=3$

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The standard form of the equation of the circle is $\boxed{(x + 8)^2 + (y - 3)^2 = 9}$.

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Step 1 ：The standard form of the equation of a circle is given by $(x-a)^2 + (y-b)^2 = r^2$, where $(a, b)$ is the center of the circle and $r$ is the radius.

Step 2 ：In this case, the center of the circle is $(-8, 3)$ and the radius is $3$.

Step 3 ：We substitute these values into the standard form to get the equation of the circle.

Step 4 ：The equation is $(x - (-8))^2 + (y - (3))^2 = 3^2$.

Step 5 ：The standard form of the equation of the circle is $\boxed{(x + 8)^2 + (y - 3)^2 = 9}$.

Write the standard form of the equation of the circle described below.Center $(-8,3), r=3$

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Write the standard form of the equation of the circle described below.
Center $(-8,3), r=3$