f(x)=frac{x-1}{x^{2}-1}

Question

Accepted Answer

Step:1 ：Given function: (f(x)=frac{x-1}{x^{2}-1})Step:2 ：Factor the denominator as a difference of squares: (x^{2}-1 = (x-1)(x+1))Step:3 ：Simplify the function by canceling out the common factors in the numerator and denominator: (f(x)=frac{x-1}{(x-1)(x+1)})Step:4 ：Final Answer: (boxed{f(x) = frac{1}{x + 1}})

Answer

Step: 1 ：Given function: (f(x)=frac{x-1}{x^{2}-1})Step: 2 ：Factor the denominator as a difference of squares: (x^{2}-1 = (x-1)(x+1))Step: 3 ：Simplify the function by canceling out the common factors in the numerator and denominator: (f(x)=frac{x-1}{(x-1)(x+1)})Step: 4 ：Final Answer: (boxed{f(x) = frac{1}{x + 1}})

$f (x) = \frac{x - 1}{x^{2} - 1}$

Answer

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f(x)=x−1x2−1

Answer

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$f (x) = \frac{x - 1}{x^{2} - 1}$