$\int \cos ^{2}(x+1) d x$ أوجد قِيمة التكامل
\(\boxed{\frac{1}{2} (x + 1 + \frac{1}{2} \sin(2(x + 1))) + C}\)
Step 1 :\(u = x + 1\)
Step 2 :\(du = dx\)
Step 3 :\(\int \cos^2(u) du\)
Step 4 :Using the double angle formula: \(\cos^2(u) = \frac{1 + \cos(2u)}{2}\)
Step 5 :\(\int \frac{1 + \cos(2u)}{2} du\)
Step 6 :\(\frac{1}{2} \int (1 + \cos(2u)) du\)
Step 7 :\(\frac{1}{2} (\int 1 du + \int \cos(2u) du)\)
Step 8 :\(\frac{1}{2} (u + \frac{1}{2} \sin(2u)) + C\)
Step 9 :Substitute back: \(\frac{1}{2} (x + 1 + \frac{1}{2} \sin(2(x + 1))) + C\)
Step 10 :\(\boxed{\frac{1}{2} (x + 1 + \frac{1}{2} \sin(2(x + 1))) + C}\)