Three children are throwing a disc in the park. The first child throws the disc $18 \mathrm{~m}\left[\mathrm{~W} 23^{\circ} \mathrm{S}\right]$ to the second child, who then throws the disc $19 \mathrm{~m}[\mathrm{E}$
4 points $\left.62^{\circ} \mathrm{S}\right]$. What is the net displacement of the disc?

Answer

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Answer

$\boxed{25.01 \mathrm{m} \left[\mathrm{W} 7.81^\circ \mathrm{S}\right]}$

Steps

Step 1 ：Find the x and y components of each throw: $x_1 = -16.57$, $y_1 = -7.03$, $x_2 = 8.92$, $y_2 = -16.78$

Step 2 ：Add the components together: $x_{net} = -7.65$, $y_{net} = -23.81$

Step 3 ：Find the magnitude and direction: $magnitude = 25.01$, $direction = 252.19^\circ$

Step 4 ：$\boxed{25.01 \mathrm{m} \left[\mathrm{W} 7.81^\circ \mathrm{S}\right]}$