frac{6 n}{n^{2}-9}-frac{3}{n+3}

Question

Accepted Answer

Step:1 ：Factor the denominator of the first term: frac{6n}{(n-3)(n+3)} - frac{3}{n+3}Step:2 ：Find a common denominator and simplify: boxed{frac{3}{n-3}}

Answer

Step: 1 ：Factor the denominator of the first term: frac{6n}{(n-3)(n+3)} - frac{3}{n+3}Step: 2 ：Find a common denominator and simplify: boxed{frac{3}{n-3}}

$\frac{6 n}{n^{2}-9}-\frac{3}{n+3}$

Answer

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