A bag contains red and green chips. Some of the chips have white stripes. The probability of drawing a green chip, $P(G)$, is 0.4 . The probability of drawing a striped chip, $P(S)$, is 0.5 . The probability of drawing a green and striped chip, $P(G$ and $S)$, is 0.3 .
Move the numbers to complete and solve the equation to determine the probability of drawing a striped chip given it is green, $P(S \mid G)$.
Answer
Plugging in the given values, we get $P(S \mid G) = \frac{0.3}{0.4} = 0.75$. So, the probability of drawing a striped chip given it is green is \(\boxed{0.75}\)
Step 1 ：We are given $P(G) = 0.4$, $P(S) = 0.5$, and $P(G \text{ and } S) = 0.3$. We need to find $P(S \mid G)$ using the conditional probability formula: $P(S \mid G) = \frac{P(S \text{ and } G)}{P(G)}$
Step 2 ：Plugging in the given values, we get $P(S \mid G) = \frac{0.3}{0.4} = 0.75$. So, the probability of drawing a striped chip given it is green is \(\boxed{0.75}\)
