A spinner has 10 equally sized sections, 7 of which are gray and 3 of which are blue. The spinner is spun twice. What is the probability that the first spin lands on gray and the second spin lands on blue?
Write your answer as a fraction in simplest form.

Answer

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Answer

$P (G \cap B) = \frac{7}{10} \cdot \frac{3}{10} = \frac{21}{100}$

Steps

Step 1 ： $P (G) = \frac{7}{10}$

Step 2 ： $P (B) = \frac{3}{10}$

Step 3 ： $P (G \cap B) = \frac{7}{10} \cdot \frac{3}{10} = \frac{21}{100}$