A spinner has 10 equally sized sections, 7 of which are gray and 3 of which are blue. The spinner is spun twice. What is the probability that the first spin lands on gray and the second spin lands on blue?
Write your answer as a fraction in simplest form.

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Answer

\( P(G \cap B) = \frac{7}{10} \cdot \frac{3}{10} = \frac{21}{100} \)

Steps

Step 1 ：\( P(G) = \frac{7}{10} \)

Step 2 ：\( P(B) = \frac{3}{10} \)

Step 3 ：\( P(G \cap B) = \frac{7}{10} \cdot \frac{3}{10} = \frac{21}{100} \)