Problem

In a system the pressure and mass are kept constant. The initial temperature of the system is \( 16.2^{\circ} \mathrm{C} \) and the volume is \( 0.75 \mathrm{~L} \). If the volume changes to \( 7.5 \mathrm{~L} \) what is the temperature in \( { }^{\circ} \mathrm{C} \) ?

Answer

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Answer

\(T_2 = \frac{V_2}{V_1} T_1 = \frac{7.5}{0.75} \times 16.2^{\circ} \mathrm{C} = 162^{\circ} \mathrm{C} \)

Steps

Step 1 ：\(T_1 = 16.2^{\circ} \mathrm{C} \), \(V_1 = 0.75 \mathrm{~L} \)

Step 2 ：\(V_2 = 7.5 \mathrm{~L} \)

Step 3 ：\(T_2 = \frac{V_2}{V_1} T_1 = \frac{7.5}{0.75} \times 16.2^{\circ} \mathrm{C} = 162^{\circ} \mathrm{C} \)

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