In a system the mass is kept constant. The initial temperature of the system is ( 87.2^{circ} mathrm{C} ), the pressure is ( 57.3 mathrm{~atm} ), and the volume is ( 3.8 mathrm{~L} ). If the volume changes to ( 8.8 mathrm{~L} ) and the pressure changes to ( 12.2 mathrm{~atm} ) what is the temperature in degrees Celsius?

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Accepted Answer

Step:1 ：( P_1V_1/T_1 = P_2V_2/T_2 )Step:2 ：( (57.3mathrm{~atm})(3.8mathrm{~L})/(87.2+273.15) = (12.2mathrm{~atm})(8.8mathrm{~L})/T_2 )Step:3 ：( T_2 = 147.6432^{circ} mathrm{C} )

Answer

Step: 1 ：( P_1V_1/T_1 = P_2V_2/T_2 )Step: 2 ：( (57.3mathrm{~atm})(3.8mathrm{~L})/(87.2+273.15) = (12.2mathrm{~atm})(8.8mathrm{~L})/T_2 )Step: 3 ：( T_2 = 147.6432^{circ} mathrm{C} )

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