In a system the mass is kept constant. The initial temperature of the system is ( 87.2^{circ} mathrm{C} ), the pressure is ( 57.3 mathrm{~atm} ), and the volume is ( 3.8 mathrm{~L} ). If the volume changes to ( 8.8 mathrm{~L} ) and the pressure changes to ( 12.2 mathrm{~atm} ) what is the temperature in degrees Celsius?

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Accepted Answer

Step:1 ：( P_1V_1/T_1 = P_2V_2/T_2 )Step:2 ：( (57.3mathrm{~atm})(3.8mathrm{~L})/(87.2+273.15) = (12.2mathrm{~atm})(8.8mathrm{~L})/T_2 )Step:3 ：( T_2 = 147.6432^{circ} mathrm{C} )

Answer

Step: 1 ：( P_1V_1/T_1 = P_2V_2/T_2 )Step: 2 ：( (57.3mathrm{~atm})(3.8mathrm{~L})/(87.2+273.15) = (12.2mathrm{~atm})(8.8mathrm{~L})/T_2 )Step: 3 ：( T_2 = 147.6432^{circ} mathrm{C} )

In a system the mass is kept constant. The initial temperature of the system is ${87.2}^{\circ} C$ , the pressure is $57.3 atm$ , and the volume is $3.8 L$ . If the volume changes to $8.8 L$ and the pressure changes to $12.2 atm$ what is the temperature in degrees Celsius?

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Popular Problems

In a system the mass is kept constant. The initial temperature of the system is 87.2∘C, the pressure is 57.3 atm, and the volume is 3.8 L. If the volume changes to 8.8 L and the pressure changes to 12.2 atm what is the temperature in degrees Celsius?

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Popular Problems

In a system the mass is kept constant. The initial temperature of the system is ${87.2}^{\circ} C$ , the pressure is $57.3 atm$ , and the volume is $3.8 L$ . If the volume changes to $8.8 L$ and the pressure changes to $12.2 atm$ what is the temperature in degrees Celsius?