In a system the temperature and mass are kept constant. The initial pressure of the system is ( 6.27 mathrm{~mm} mathrm{Hg} ). If the pressure changes to 2.8 ( mathrm{mm} mathrm{Hg} ) when the volume changes to ( 0.765 mathrm{~L} ) what was the original volume?

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Step:1 ：1. Use Boyle&#x27;s Law: (P_1V_1=P_2V_2)Step:2 ：2. Solve for (V_1): (V_1=frac{P_2V_2}{P_1})Step:3 ：3. Substitute values: (V_1=frac{(2.8 mathrm{~mm} mathrm{Hg})(0.765 mathrm{~L})}{6.27 mathrm{~mm} mathrm{Hg}})

Answer

Step: 1 ：1. Use Boyle&#x27;s Law: (P_1V_1=P_2V_2)Step: 2 ：2. Solve for (V_1): (V_1=frac{P_2V_2}{P_1})Step: 3 ：3. Substitute values: (V_1=frac{(2.8 mathrm{~mm} mathrm{Hg})(0.765 mathrm{~L})}{6.27 mathrm{~mm} mathrm{Hg}})

In a system the temperature and mass are kept constant. The initial pressure of the system is $6.27 mm Hg$ . If the pressure changes to 2.8 $mm Hg$ when the volume changes to $0.765 L$ what was the original volume?

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Popular Problems

In a system the temperature and mass are kept constant. The initial pressure of the system is 6.27 mmHg. If the pressure changes to 2.8 mmHg when the volume changes to 0.765 L what was the original volume?

Answer

Popular Problems

In a system the temperature and mass are kept constant. The initial pressure of the system is $6.27 mm Hg$ . If the pressure changes to 2.8 $mm Hg$ when the volume changes to $0.765 L$ what was the original volume?