The weight of oranges growing in an orchard is normally distributed with a mean weight of ( 7 mathrm{oz} ). and a standard deviation of ( 1 mathrm{oz} ). Using the empirical rule, what percentage of the oranges from the orchard weigh between ( 4 mathrm{oz} ), and ( 10 mathrm{oz} ) ?

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Step:1 ：Find the difference between the given weight and mean weight in terms of standard deviations.Step:2 ：Use empirical rule: 68-95-99.7% rule.Step:3 ：Determine the percentage of oranges between the given weights.

Answer

Step: 1 ：Find the difference between the given weight and mean weight in terms of standard deviations.Step: 2 ：Use empirical rule: 68-95-99.7% rule.Step: 3 ：Determine the percentage of oranges between the given weights.

The weight of oranges growing in an orchard is normally distributed with a mean weight of $7 oz$ . and a standard deviation of $1 oz$ . Using the empirical rule, what percentage of the oranges from the orchard weigh between $4 oz$ , and $10 oz$ ?

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The weight of oranges growing in an orchard is normally distributed with a mean weight of 7oz. and a standard deviation of 1oz. Using the empirical rule, what percentage of the oranges from the orchard weigh between 4oz, and 10oz ?

Answer

Popular Problems

The weight of oranges growing in an orchard is normally distributed with a mean weight of $7 oz$ . and a standard deviation of $1 oz$ . Using the empirical rule, what percentage of the oranges from the orchard weigh between $4 oz$ , and $10 oz$ ?