In a system the mass is kept constant. The initial temperature of the system is ( 91.2^{circ} mathrm{C} ), the pressure is ( 2.93 mathrm{~atm} ), and the volume is ( 6.7 mathrm{~L} ). If the temperature changes to ( 18.5^{circ} mathrm{C} ) and the volume changes to ( 20.2 mathrm{~L} ) what is the pressure?

Question

Accepted Answer

Step:1 ：1. Convert Celsius to Kelvin: (T_1 = 91.2^{circ} mathrm{C} + 273.15 = 364.35 mathrm{K} ), (T_2 = 18.5^{circ} mathrm{C} + 273.15 = 291.65 mathrm{K} )Step:2 ：2. Use the combined gas law: (frac{P_1V_1}{T_1} = frac{P_2V_2}{T_2} )Step:3 ：3. Solve for (P_2): (P_2 = frac{P_1V_1T_2}{T_1V_2} = frac{2.93 mathrm{~atm} cdot 6.7 mathrm{~L} cdot 291.65 mathrm{K}}{364.35 mathrm{K} cdot 20.2 mathrm{~L}} = 1.0511 mathrm{~atm} )

Answer

Step: 1 ：1. Convert Celsius to Kelvin: (T_1 = 91.2^{circ} mathrm{C} + 273.15 = 364.35 mathrm{K} ), (T_2 = 18.5^{circ} mathrm{C} + 273.15 = 291.65 mathrm{K} )Step: 2 ：2. Use the combined gas law: (frac{P_1V_1}{T_1} = frac{P_2V_2}{T_2} )Step: 3 ：3. Solve for (P_2): (P_2 = frac{P_1V_1T_2}{T_1V_2} = frac{2.93 mathrm{~atm} cdot 6.7 mathrm{~L} cdot 291.65 mathrm{K}}{364.35 mathrm{K} cdot 20.2 mathrm{~L}} = 1.0511 mathrm{~atm} )

In a system the mass is kept constant. The initial temperature of the system is ${91.2}^{\circ} C$ , the pressure is $2.93 atm$ , and the volume is $6.7 L$ . If the temperature changes to ${18.5}^{\circ} C$ and the volume changes to $20.2 L$ what is the pressure?

Answer

Popular Problems

In a system the mass is kept constant. The initial temperature of the system is 91.2∘C, the pressure is 2.93 atm, and the volume is 6.7 L. If the temperature changes to 18.5∘C and the volume changes to 20.2 L what is the pressure?

Answer

Popular Problems

In a system the mass is kept constant. The initial temperature of the system is ${91.2}^{\circ} C$ , the pressure is $2.93 atm$ , and the volume is $6.7 L$ . If the temperature changes to ${18.5}^{\circ} C$ and the volume changes to $20.2 L$ what is the pressure?