In a system the volume and mass are kept constant. The initial temperature of the system is ( 120^{circ} mathrm{C} ) and the pressure is ( 61.2 mathrm{~atm} ). If the temperature changes to ( -14^{circ} mathrm{C} ) what is the pressure?

Question

Accepted Answer

Step:1 ：1. Apply Gay-Lussac&#x27;s Law: (frac{P_1}{T_1} = frac{P_2}{T_2})Step:2 ：2. Convert temperatures to Kelvin: (T_1 = 393.15mathrm{~K},~ T_2 = 259.15mathrm{~K})Step:3 ：3. Calculate the new pressure: (P_2 = frac{P_1 T_2}{T_1} = frac{61.2mathrm{~atm} cdot 259.15mathrm{~K}}{393.15mathrm{~K}})

Answer

Step: 1 ：1. Apply Gay-Lussac&#x27;s Law: (frac{P_1}{T_1} = frac{P_2}{T_2})Step: 2 ：2. Convert temperatures to Kelvin: (T_1 = 393.15mathrm{~K},~ T_2 = 259.15mathrm{~K})Step: 3 ：3. Calculate the new pressure: (P_2 = frac{P_1 T_2}{T_1} = frac{61.2mathrm{~atm} cdot 259.15mathrm{~K}}{393.15mathrm{~K}})

In a system the volume and mass are kept constant. The initial temperature of the system is $120^{\circ} C$ and the pressure is $61.2 atm$ . If the temperature changes to $- 14^{\circ} C$ what is the pressure?

Answer

Popular Problems

In a system the volume and mass are kept constant. The initial temperature of the system is 120∘C and the pressure is 61.2 atm. If the temperature changes to −14∘C what is the pressure?

Answer

Popular Problems

In a system the volume and mass are kept constant. The initial temperature of the system is $120^{\circ} C$ and the pressure is $61.2 atm$ . If the temperature changes to $- 14^{\circ} C$ what is the pressure?