In a system the mass is kept constant. The initial temperature of the system is 31.1∘C, the pressure is 0.61 atm, and the volume is 3 L. If the temperature changes to 145.7∘C and the pressure changes to 2.3 atm what is the volume?
V2=P1V1T2P2T1=0.61 atm⋅3 L⋅418.85 K2.3 atm⋅304.25 K=1.3225 L
Step 1 :T1=31.1+273.15=304.25 K
Step 2 :T2=145.7+273.15=418.85 K
Step 3 :V2=P1V1T2P2T1=0.61 atm⋅3 L⋅418.85 K2.3 atm⋅304.25 K=1.3225 L