Problem

In a system the temperature and mass are kept constant. The initial pressure of the system is \( 11.8 \mathrm{~atm} \) and the volume is \( 3.41 \mathrm{~L} \). If the volume changes to \( 5.65 \mathrm{~L} \) what is the pressure?

Answer

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Answer

3. \( P_2 = \frac{(11.8\mathrm{~atm})(3.41\mathrm{~L})}{5.65\mathrm{~L}} = 7.1409\mathrm{~atm} \)

Steps

Step 1 ：1. \( P_1V_1 = P_2V_2 \)

Step 2 ：2. \( (11.8\mathrm{~atm})(3.41\mathrm{~L}) = P_2(5.65\mathrm{~L}) \)

Step 3 ：3. \( P_2 = \frac{(11.8\mathrm{~atm})(3.41\mathrm{~L})}{5.65\mathrm{~L}} = 7.1409\mathrm{~atm} \)

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