Given that f(x)=x+2,g(x)=−5x and h(x)=2f(x−2)−3g(x−3), then what is the value of h(6) ?
h(6)=57
Step 1 :h(x)=2f(x−2)−3g(x−3)
Step 2 :h(6)=2f(6−2)−3g(6−3)
Step 3 :h(6)=2f(4)−3g(3)
Step 4 :f(x)=x+2
Step 5 :f(4)=4+2
Step 6 :f(4)=6
Step 7 :g(x)=−5x
Step 8 :g(3)=−5(3)
Step 9 :g(3)=−15
Step 10 :h(6)=2(6)−3(−15)
Step 11 :h(6)=12+45
Step 12 :h(6)=57