Given that f(x)=−2x,g(x)=x−5 and h(x)=3f(x−2)+g(x), then what is the value of h(2) ?
h(2)=−3
Step 1 :h(x)=3f(x−2)+g(x)
Step 2 :h(2)=3f(0)+g(2)
Step 3 :h(2)=−3