4. (MGSE9.12 ACED.2, MGSF9-12. B.BF.1) Complete the square to write $c (x) = x^{2} + 6 x +$ 14 in vertes form.
A. $c (x) = (x + 3)^{2} + 5$
8. $c (x) = (x - 3)^{2} + 14$
$c (t) = (2 + 3)^{2} + 23$
D. $r (x) = (x + 6)^{2} + 14$

Answer

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Answer

$c (x) = (x + 3)^{2} + 5$

Steps

Step 1 ： $c (x) = x^{2} + 6 x + 14$

Step 2 ： $c (x) = (x^{2} + 6 x + 9) + 14 - 9$

Step 3 ： $c (x) = (x + 3)^{2} + 5$