( int_{0}^{3} x^{2}-3 x-9 )

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Accepted Answer

Step:1 ：( int x^{2}-3 x-9,mathrm{d}x = int x^2,mathrm{d}x - int 3x,mathrm{d}x - int 9,mathrm{d}x )Step:2 ：( int x^2,mathrm{d}x = frac{1}{3}x^3 + C_1 )Step:3 ：( int 3x,mathrm{d}x = frac{3}{2}x^2 + C_2 )Step:4 ：( int 9,mathrm{d}x = 9x + C_3 )Step:5 ：( int x^{2}-3 x-9,mathrm{d}x = left( frac{1}{3}x^3 - frac{3}{2}x^2 - 9x right) + C )Step:6 ：( begin{split} int_{0}^{3} x^{2}-3 x-9,mathrm{d}x = left[ frac{1}{3}x^3 - frac{3}{2}x^2 - 9x right]_0^3 end{split})

Answer

Step: 1 ：( int x^{2}-3 x-9,mathrm{d}x = int x^2,mathrm{d}x - int 3x,mathrm{d}x - int 9,mathrm{d}x )Step: 2 ：( int x^2,mathrm{d}x = frac{1}{3}x^3 + C_1 )Step: 3 ：( int 3x,mathrm{d}x = frac{3}{2}x^2 + C_2 )Step: 4 ：( int 9,mathrm{d}x = 9x + C_3 )Step: 5 ：( int x^{2}-3 x-9,mathrm{d}x = left( frac{1}{3}x^3 - frac{3}{2}x^2 - 9x right) + C )Step: 6 ：( begin{split} int_{0}^{3} x^{2}-3 x-9,mathrm{d}x = left[ frac{1}{3}x^3 - frac{3}{2}x^2 - 9x right]_0^3 end{split})

$\int_{0}^{3} x^{2} - 3 x - 9$

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$\int_{0}^{3} x^{2} - 3 x - 9$