Find the derivative of the function.
\[
\begin{array}{r}
h(x)=e^{x+9} \\
h^{\prime}(x)=\square
\end{array}
\]
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Final Answer: The derivative of the function \(h(x)=e^{x+9}\) is \(h^{\prime}(x)=e^{x+9}\). So, \(h^{\prime}(x)=\boxed{e^{x+9}}\).
Step 1 :The derivative of a function can be found using the rules of differentiation. In this case, we have an exponential function. The derivative of an exponential function is simply the original function itself multiplied by the derivative of the exponent. In this case, the exponent is x+9, and its derivative is 1. Therefore, the derivative of the function \(h(x) = e^{x+9}\) is simply \(e^{x+9} * 1 = e^{x+9}\).
Step 2 :Final Answer: The derivative of the function \(h(x)=e^{x+9}\) is \(h^{\prime}(x)=e^{x+9}\). So, \(h^{\prime}(x)=\boxed{e^{x+9}}\).