Find the value of $z_{\alpha}$.
\[
\alpha=0.12
\]
The value of $z_{0.12}$ is (Round to two decimal places as needed.)

Answer

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Answer

Final Answer: The value of $z_{0.12}$ is $\boxed{-1.17}$.

Steps

Step 1 ：Given that $\alpha=0.12$, we are asked to find the z-score that corresponds to the 12th percentile in a standard normal distribution.

Step 2 ：We can use the inverse of the cumulative distribution function (CDF) to find this z-score, which returns the x-value that corresponds to a given percentile.

Step 3 ：After calculation, we find that $z_{\alpha} = -1.1749867920660904$.

Step 4 ：Rounding to two decimal places as needed, we get $z_{\alpha} = -1.17$.

Step 5 ：Final Answer: The value of $z_{0.12}$ is $\boxed{-1.17}$.

Find the value of $z_{\alpha}$.\[\alpha=0.12\]The value of $z_{0.12}$ is (Round to two decimal places as needed.)

Answer

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Find the value of $z_{\alpha}$.
\[
\alpha=0.12
\]
The value of $z_{0.12}$ is (Round to two decimal places as needed.)