Find the terminal point on the unit circle determined by $\frac{5 \pi}{3}$ radians.
Use exact values, not decimal approximations.
\[
(x, y)=(\mathbb{1}, \square)
\]
Final Answer: The terminal point on the unit circle determined by \(\frac{5 \pi}{3}\) radians is \(\boxed{(\frac{1}{2}, -\frac{\sqrt{3}}{2})}\)
Step 1 :The terminal point on the unit circle is given by the coordinates (cos(theta), sin(theta)). Here, theta is the angle in radians, which is given as \(\frac{5 \pi}{3}\). So, we need to find the cosine and sine of \(\frac{5 \pi}{3}\).
Step 2 :The cosine of \(\frac{5 \pi}{3}\) is approximately 0.5 and the sine of \(\frac{5 \pi}{3}\) is approximately -0.866. However, we need to provide the exact values.
Step 3 :The exact value of cos(\(\frac{5 \pi}{3}\)) is \(\frac{1}{2}\) and the exact value of sin(\(\frac{5 \pi}{3}\)) is \(-\frac{\sqrt{3}}{2}\).
Step 4 :Final Answer: The terminal point on the unit circle determined by \(\frac{5 \pi}{3}\) radians is \(\boxed{(\frac{1}{2}, -\frac{\sqrt{3}}{2})}\)