Solve the equation for exact solutions in the interval $\left[0^{\circ}, 360^{\circ}\right)$. Use an algebraic method.
\[
6 \sec ^{2} \theta \tan \theta=8 \tan \theta
\]
Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A. The solution set is
(Simplify your answer. Type an integer or a fraction. Use a comma to separate answers as needed. Do not include the degree symbol in your answer.)
B. The solution is the empty set.

Step 1 ：The given equation is \(6 \sec ^{2} \theta \tan \theta=8 \tan \theta\).

Step 2 ：We can simplify this equation by dividing both sides by \(\tan \theta\), assuming \(\tan \theta \neq 0\). This gives us \(6 \sec ^{2} \theta = 8\).

Step 3 ：We can further simplify this by noting that \(\sec \theta = \frac{1}{\cos \theta}\), so the equation becomes \(6 \left(\frac{1}{\cos^2 \theta}\right) = 8\).

Step 4 ：Solving this for \(\cos \theta\) will give us the solutions for \(\theta\) in the interval \([0^{\circ}, 360^{\circ})\).

Step 5 ：The solutions obtained are in radians. We need to convert these to degrees to match the interval given in the question.

Step 6 ：We also need to consider the case when \(\tan \theta = 0\), which we initially assumed to be non-zero to simplify the equation. The values of \(\theta\) for which \(\tan \theta = 0\) in the interval \([0^{\circ}, 360^{\circ})\) are \(0^{\circ}\) and \(180^{\circ}\).

Step 7 ：Combining all the solutions, we get \(\theta\) = \(0^{\circ}, 30^{\circ}, 150^{\circ}, 180^{\circ}, 210^{\circ}, 330^{\circ}\).

Step 8 ：Final Answer: The solution set is \(\boxed{0^{\circ}, 30^{\circ}, 150^{\circ}, 180^{\circ}, 210^{\circ}, 330^{\circ}}\).