Find the margin of error for the given values of $c, \sigma$, and $n$.
\[
c=0.90, \sigma=2.5, n=100
\]
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$E=\square$ (Round to three decimal places as needed.)

Step 1 ：We are given the following values: confidence level (c) = 0.90, standard deviation (σ) = 2.5, and sample size (n) = 100.

Step 2 ：The z-score corresponding to a confidence level of 0.90 is approximately 1.645.

Step 3 ：The formula to calculate the margin of error (E) for a confidence interval is \(E = z * \frac{\sigma}{\sqrt{n}}\).

Step 4 ：Substituting the given values into the formula, we get \(E = 1.645 * \frac{2.5}{\sqrt{100}}\).

Step 5 ：Solving the above expression, we find that \(E = 0.41125\).

Step 6 ：Rounding to three decimal places as needed, we get \(E = 0.411\).

Step 7 ：Final Answer: The margin of error for the given values is \(\boxed{0.411}\).