Find the exact value of $s$ in the given interval that has the given circular function value. Do not use a calculator.
\[
\left[\pi, \frac{3 \pi}{2}\right] ; \tan s=\frac{\sqrt{3}}{3}
\]
\[
s=
\]
radians
(Simplify your answer. Type an exact answer, using $\pi$ as needed. Use integers or fractions for any numbers in the expression.)

Step 1 ：The tangent function is positive in the first and third quadrants. The interval given, \([\pi, \frac{3 \pi}{2}]\), is in the third quadrant.

Step 2 ：The value of \(\tan s=\frac{\sqrt{3}}{3}\) corresponds to an angle of \(\frac{\pi}{6}\) in the first quadrant.

Step 3 ：However, since we are in the third quadrant, we need to add \(\pi\) to this angle to get the corresponding angle in the third quadrant.

Step 4 ：\(\text{first_quadrant_angle} = \frac{\pi}{6}\)

Step 5 ：\(\text{third_quadrant_angle} = \frac{7\pi}{6}\)

Step 6 ：\(\boxed{\text{The exact value of } s \text{ in the given interval that has the given circular function value is } \frac{7\pi}{6} \text{ radians.}}\)