Problem

Use the given confidence interval to find the margin of error and the sample proportion.
\[
(0.602,0.632)
\]
$E=\square($ Type an integer or a decimal.)

Answer

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Answer

Final Answer: The margin of error (E) is \(\boxed{0.015}\) and the sample proportion (p̂) is \(\boxed{0.617}\).

Steps

Step 1 :The given confidence interval is \((0.602,0.632)\).

Step 2 :The margin of error (E) in a confidence interval is calculated as the difference between the upper limit and the lower limit divided by 2. So, the margin of error can be calculated as \((0.632 - 0.602) / 2\).

Step 3 :The sample proportion (p̂) is the midpoint of the confidence interval, which can be calculated as the sum of the upper limit and the lower limit divided by 2. So, the sample proportion can be calculated as \((0.632 + 0.602) / 2\).

Step 4 :By calculating the above expressions, we find that the margin of error (E) is \(0.015\) and the sample proportion (p̂) is \(0.617\).

Step 5 :Final Answer: The margin of error (E) is \(\boxed{0.015}\) and the sample proportion (p̂) is \(\boxed{0.617}\).

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