Question 2
The city of Raleigh has 11300 registered voters. There are two candidates for city council in an upcoming election: Brown and Feliz. The day before the election, a telephone poll of 400 randomly selected registered voters was conducted. 149 said they'd vote for Brown, 242 said they'd vote for Feliz, and 9 were undecided.

Give the sample statistic for the proportion of voters surveyed who said they'd vote for Brown. Note: The proportion should be a fraction or decimal, not a percent.
This sample statistic suggests that we might expect of the 11300 registered voters to vote for Brown.

Step 1 ：Given that the number of voters who said they'd vote for Brown is 149 and the total number of voters surveyed is 400, we can calculate the sample statistic for the proportion of voters surveyed who said they'd vote for Brown by dividing the number of voters who said they'd vote for Brown by the total number of voters surveyed. This will give us a decimal representation of the proportion.

Step 2 ：\[\frac{149}{400} = 0.3725\]

Step 3 ：To estimate the number of the 11300 registered voters who might vote for Brown, we can multiply the sample statistic by the total number of registered voters.

Step 4 ：\[0.3725 \times 11300 = 4209.25\]

Step 5 ：Since the number of voters cannot be a decimal, we round it to the nearest whole number.

Step 6 ：\[\text{Rounded number of voters} = \text{round}(4209.25) = 4209\]

Step 7 ：Final Answer: The sample statistic for the proportion of voters surveyed who said they'd vote for Brown is \(\boxed{0.3725}\). This suggests that we might expect approximately \(\boxed{4209}\) of the 11300 registered voters to vote for Brown.