Problem

The cost function for a certain commodity is
\[
C(q)=88+0.19 q-0.007 q^{2}+0.0008 q^{3} .
\]
(a) Find $C^{\prime}(100)$.
Interpret $C^{\prime}(100)$.
This is the rate at which costs are increasing with respect to the production level when $x=100$.
This is the amount of time, in minutes, it takes to produce 100 items.
This is the number of items that must be produced before the costs reach 100 .
This is the cost of making 100 items.
This is the rate at which the production level is decreasing with respect to the cost when $x=100$.
(b) Find the actual cost of manufacturing the 101st item. (Round your answer to the nearest cent.) $\$$
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Answer

Final Answer: The rate of change of the cost with respect to the quantity produced when the quantity is 100 is \(\boxed{22.79}\)

Steps

Step 1 :Given the cost function \(C(q)=88+0.19 q-0.007 q^{2}+0.0008 q^{3}\)

Step 2 :We need to find the derivative of the cost function, \(C'(q)\), which gives the rate of change of the cost with respect to the quantity produced.

Step 3 :Using the power rule for differentiation, the derivative of \(C(q)\) is \(C'(q) = 0.19 - 0.014q + 0.0024q^{2}\)

Step 4 :Substitute \(q=100\) into the derivative function to find the rate of change of the cost at \(q=100\), \(C'(100) = 22.79\)

Step 5 :Final Answer: The rate of change of the cost with respect to the quantity produced when the quantity is 100 is \(\boxed{22.79}\)

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