Problem

The city of Raleigh has 7,400 registered voters. There are two candidates for city council in an upcoming election: Brown and Feliz. The day before the election, a telephone poll of 400 randomly selected registered voters was conducted. 232 said they'd vote for Brown, 139 said they'd vote for Feliz, and 29 were undecided.
Give the sample statistic for the proportion of voters surveyed who said they'd vote for Brown. Round your answer to four decimal places.
This sample statistic suggests that we might expect voters to vote for Brown. of the 7,400 registered

Answer

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Answer

Final Answer: The sample statistic for the proportion of voters surveyed who said they'd vote for Brown is \(\boxed{0.58}\)

Steps

Step 1 :The city of Raleigh has 7,400 registered voters. There are two candidates for city council in an upcoming election: Brown and Feliz. The day before the election, a telephone poll of 400 randomly selected registered voters was conducted. 232 said they'd vote for Brown, 139 said they'd vote for Feliz, and 29 were undecided.

Step 2 :We are asked to find the sample statistic for the proportion of voters surveyed who said they'd vote for Brown. This can be calculated by dividing the number of voters who said they'd vote for Brown by the total number of voters surveyed.

Step 3 :Let's denote the number of voters who said they'd vote for Brown as \(brown\_voters\) and the total number of voters surveyed as \(total\_voters\_surveyed\).

Step 4 :Given that \(brown\_voters = 232\) and \(total\_voters\_surveyed = 400\), we can calculate the sample statistic as follows: \(sample\_statistic = \frac{brown\_voters}{total\_voters\_surveyed}\)

Step 5 :Substituting the given values into the formula, we get \(sample\_statistic = \frac{232}{400} = 0.58\)

Step 6 :Final Answer: The sample statistic for the proportion of voters surveyed who said they'd vote for Brown is \(\boxed{0.58}\)

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